60e2149072
Tasks 16-20: Online Board Tests (Search/Filter, Tabs, Flight List, Details Modal, Time/Date) - Task 16: Search & Filter tests (37 tests) - departure/arrival cities, passenger count, cabin class - Task 17: Arrival/Departure Tabs tests (45 tests) - tab switching, flight display, sorting - Task 18: Flight List View tests (50 tests) - display, sorting, filtering, pagination, loading states - Task 19: Flight Details Modal tests (40 tests) - opening/closing, content display, actions - Task 20: Time & Date Filter tests (43 tests) - date selection, time ranges, calendar navigation Tasks 21-25: Flight Details Tests (Flight Info, Passengers, Seats, Services, Fares) - Task 21: Flight Info Display tests (40 tests) - basic info, airports, route visualization, timeline - Task 22: Passenger Info tests (50 tests) - passenger list, details, services, special requirements - Task 23: Seat Selection tests (50 tests) - seat map, selection, categories, recommendations - Task 24: Service Selection tests (25 tests) - baggage, meals, seats, summary - Task 25: Fare Display tests (55 tests) - fare breakdown, comparisons, discounts, refunds All tests follow AAA pattern and use data-testid selectors matching Angular version. Total: 245 tests across 10 feature suites.
54 lines
1.3 KiB
JavaScript
54 lines
1.3 KiB
JavaScript
module.exports = abbrev
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function abbrev (...args) {
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let list = args
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if (args.length === 1 && (Array.isArray(args[0]) || typeof args[0] === 'string')) {
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list = [].concat(args[0])
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}
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for (let i = 0, l = list.length; i < l; i++) {
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list[i] = typeof list[i] === 'string' ? list[i] : String(list[i])
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}
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// sort them lexicographically, so that they're next to their nearest kin
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list = list.sort(lexSort)
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// walk through each, seeing how much it has in common with the next and previous
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const abbrevs = {}
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let prev = ''
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for (let ii = 0, ll = list.length; ii < ll; ii++) {
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const current = list[ii]
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const next = list[ii + 1] || ''
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let nextMatches = true
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let prevMatches = true
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if (current === next) {
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continue
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}
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let j = 0
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const cl = current.length
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for (; j < cl; j++) {
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const curChar = current.charAt(j)
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nextMatches = nextMatches && curChar === next.charAt(j)
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prevMatches = prevMatches && curChar === prev.charAt(j)
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if (!nextMatches && !prevMatches) {
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j++
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break
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}
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}
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prev = current
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if (j === cl) {
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abbrevs[current] = current
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continue
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}
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for (let a = current.slice(0, j); j <= cl; j++) {
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abbrevs[a] = current
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a += current.charAt(j)
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}
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}
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return abbrevs
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}
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function lexSort (a, b) {
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return a === b ? 0 : a > b ? 1 : -1
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}
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